Question #98859
A small artery has a length of 1.1x10 m and a radius
of 2.5x 10 m . If the pressure drop across the artery is
1.3.kPa, what is the flow rate through the artery? (Assume
that the temperature is 37°C.)
1
Expert's answer
2019-11-18T10:43:30-0500
η=2.1103Nsm2\eta = 2.1\cdot 10^{-3} \frac{Ns}{m^2}

Hagen–Poiseuille equation:

Δp=8ηLQπR4\Delta p =\frac{ 8\eta LQ}{\pi R^4}

(1.3103)=8(2.1103)(1.1103)Qπ(2.5105)4(1.3\cdot 10^{3}) =\frac{ 8(2.1\cdot 10^{-3})(1.1\cdot 10^{-3})Q}{\pi (2.5\cdot 10^{-5})^4}

Q=8.71011m3sQ=8.7\cdot 10^{-11}\frac{m^3}{s}


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