Question

A defective SUV with a mass of 2200 kg is towed at a uniform speed of 12 m / s along roads with a 4.0 kN horizontal force. How much work is done on the SUV in 50.0 seconds?

Answer 1

The work is

$$W=Pt=Fvt$$

$$W=(4000)(12)(50)=2400000\ J=2.4\ MJ$$