gas cylinder is able to withstand a maximum pressure of 1.20 x 10^6 Pa the cylinder has a volume of 3.00 X 10^-4 m3 it contains 3.00 x 10^22 molecules of gas. calculate using the ideal gay equation the temperature of the gas at maximum pressure
"(1.2\\cdot 10^{6})(3\\cdot 10^{-4})=\\frac{3\\cdot 10^{22}}{6.02\\cdot 10^{23}}(8.31)T"
"T=869\\ K"
Comments
Leave a comment