Question

A crate is pulled by a force (parallel to the
incline) up a rough incline. The crate has an
initial speed shown in the figure below. The
crate is pulled a distance of 7.99 m on the
incline by a 150 N force.
The acceleration of gravity is 9.8 m/s2.
a) What is the change in kinetic energy of
the crate?
Answer in units of J.
Don't round answer.

Answer 1

From the conservation of energy:

$$\Delta K=Fd-mgh-\mu mgd\cos{23}=Fd-mgd(\sin{23}+\mu \cos{23})$$

$$\Delta K=(150-(13)(9.8)(\sin{23}+0.318 \cos{23}))7.99=503\ J$$