The maximum height
In the first case, when projectile is fired straight up
In the second case, when projectile is fired at an angle of 30° from the vertical
"h_{max}=\\frac{(v_0\\cos 30^\\circ)^2}{2g}=\\frac{(v_0\\times \\sqrt{3}\/2)^2}{2g}=\\frac{3}{4}h"
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