Question #98371
One mole of a monatomic ideal gas is initially at 273 K and 1 atm. (a) What is the initial internal energy of the gas? (b) Find the work done on the gas when 500 J of heat are absorbed by the gas at constant pressure. What is the final internal energy of the gas? (c) Find the work done on the gas when 500 J of heat are absorbed by the gas at constant volume. What is the final internal energy of the gas?
1
Expert's answer
2019-11-11T15:57:25-0500

a)


Ui=32nRT1=32(1)(8.31)(273)=3400 JU_i=\frac{3}{2}nRT_1=\frac{3}{2}(1)(8.31)(273)=3400\ J

b)


W=QΔU=52nR(T2T1)32nR(T2T1)=nR(T2T1)W=Q-\Delta U=\frac{5}{2}nR(T_2-T_1)-\frac{3}{2}nR(T_2-T_1)=nR(T_2-T_1)

Q=52nR(T2T1)Q=\frac{5}{2}nR(T_2-T_1)

W=25Q=25500=200 JW=\frac{2}{5}Q=\frac{2}{5}500=200\ J

c)


W=0 JW=0\ J

Uf=Ui+Q=3400+500=3900 JU_f=U_i+Q=3400+500=3900\ J


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