Question

What will be the velocity of the particle that is 1.8 m away from the centre on the minutes hand clock?

Answer 1

The linear velocity

$$v=\omega R=\frac{2\pi }{T}R$$

$$=\frac{2\pi }{3600\:\rm s}\times 1.8\:\rm m=0.00314‬ \:m/s=3.14\: mm/s$$