Question #97785
A block of mass m is pushed a horizontal distance D from position A to position B, along
a horizontal plane with friction coefficient µ.
Then the mass is pushed from B to A.
If the horizontal force pushing the mass
from A to B is P~ , and the force pushing the
mass from B to A is −P~ , what is the total
work done by friction?
1. +2 µ m g D
2. −2 µ m g D
3. 2 (P − µ m g) D
4. 2 (µ m g − P) D
5. 0
1
Expert's answer
2019-11-05T10:39:37-0500

The work done

W=FdcosθW=Fd\cos\theta

WAB=μmgDW_{AB}=-\mu mgD

WBA=μmgDW_{BA}=-\mu mgD

So, the total work done by friction


W=WAB+WBA=2μmgDW=W_{AB}+W_{BA}=-2\mu mgD


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