Question

Find value of the force needed to pull a wheel of mass 1000kg with radius 1.0m over the step of 0.4m

Answer 1

$$mg\sqrt{2rh-h^2}=F(r-h)$$

$$F=mg\frac{\sqrt{2rh-h^2}}{r-h}$$

$$F=(1000)(9.8)\frac{\sqrt{2(1)(0.4)-0.4^2}}{1-0.4}=13000\ N$$