Question #96872
a stone attached to the end of an inelastic string is whirled round in a circular path of radius 30cm if the stone makes 9 complete revolutions in 3 seconds, calculate its angular and linear velocities.
1
Expert's answer
2019-10-21T09:01:39-0400

The period of revolution of the stone


T=tN=3s9=13sT=\frac{t}{N}=\frac{3\:\rm s}{9}=\frac{1}{3}\:\rm s

The angular velocity of the stone

ω=2πT=2π1/3s=6πs1=18.84s1\omega=\frac{2\pi}{T}=\frac{2\pi}{1/3\:\rm s}=6\pi\:\rm s^{-1}=18.84\:\rm s^{-1}

The linear velocity of the stone


v=ωR=6πs1×0.3m=5.652m/sv=\omega R=6\pi\:\rm s^{-1}\times 0.3\:\rm m=5.652\: \rm m/s


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Comments

Falumanye Amos
21.02.24, 14:55

Thanks

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