Question

A student placed a drop of olive oil of volume 3.8*10 raise to power -2 m raise to power 3 on the surface of a still water and the drop spreads to form a circular film of radius 0.67m. Calculate the thickness of the oil film

Answer 1

$$V=Ah=\pi r^2h$$

$$h=\frac{V}{\pi r^2}=\frac{3.8\cdot 10^{-2}}{\pi (0.67)^2}=0.027\ m$$