Question

a car moving at 10m/s accelerated uniformly through a distance of 25m/s at the end which the velocity of the car became 15m/s.
determine the acceleration of the car and the time taken to cover 25m

Answer 1

The distance traveled by car

$$d=\frac{v_f^2-v_i^2}{2a}$$

So, acceleration of the car

$$a=\frac{v_f^2-v_i^2}{2d}=\frac{15^2-10^2}{2\times 25}=2.5\:\rm m/s^2$$

Time of motion

$$t=\frac{v_f-v_i}{a}=\frac{15-10}{2.5}=2\:\rm s$$