Question

A projectile is launched from and returns to ground level. Air resistance is absent. The horizontal range of the projectile is measured to be R = 175 m, and the horizontal component of the launch velocity is Vox = 25 m/s. Find the vertical component Voy of the launch velocity.

Answer 1

$$R=\frac{v^2\sin{2\theta}}{g}$$ $$V_{0x}=vcos{\theta}=25$$

V_{0y}=vcos{\theta}

$$V_{0y}=vsin{\theta}$$

$$V_y=v\cos\theta=17\frac{m}{s}$$