The period of a boy motion along circular track "T=2t=40\\:\\rm s."
The angular speed
"\\omega=\\frac{2\\pi}{T}=\\frac{2\\pi}{40\\:\\rm s}=\\frac{\\pi}{20}\\:\\rm s^{-1}=0.079\\:s^{-1}."The linear speed
"v=\\frac{2\\pi R}{T}=\\frac{2\\pi\\times 7.5\\:\\rm m}{40\\:\\rm s}=\\frac{3\\pi}{8}\\:\\rm m\/s=1.178\\: m\/s."
Comments
Leave a comment