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Question #94583
Convert normal blood pressure readings of 120 over 80 mm Hg to newtons per meter squared using the relationship for pressure due to the weight of a fluid (P=phg) rarher than a conversion factor
Expert's answer
The deinsity of mercury is
ρ
=
13600
k
g
m
3
\rho=13600\frac{kg}{m^3}
ρ
=
13600
m
3
k
g
P
1
=
ρ
g
h
1
=
(
13600
)
(
9.8
)
(
0.12
)
=
16000
N
m
2
P_1=\rho g h_1=(13600)(9.8)(0.12)=16000\frac{N}{m^2}
P
1
=
ρ
g
h
1
=
(
13600
)
(
9.8
)
(
0.12
)
=
16000
m
2
N
P
2
=
ρ
g
h
2
=
(
13600
)
(
9.8
)
(
0.08
)
=
10700
N
m
2
P_2=\rho g h_2=(13600)(9.8)(0.08)=10700\frac{N}{m^2}
P
2
=
ρ
g
h
2
=
(
13600
)
(
9.8
)
(
0.08
)
=
10700
m
2
N
The normal blood pressure lies between these two values.
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