Question #93299
Planet Saturn =5.87 * 10^7 m and it's mass is 5.86 * 10^26 Kg find the density of its material by g/m3
Find it's surface area by m2( 4πr^2)
1
Expert's answer
2019-08-26T10:44:57-0400

The density of the Saturn


ρ=MV=M43πR3=3M4πR3\rho=\frac{M}{V}=\frac{M}{\frac{4}{3}\pi R^3}=\frac{3M}{4\pi R^3}

=3×5.86×1026kg4×3.14×(5.87×107m)3=\frac{3\times 5.86\times 10^{26}\:\rm{kg}}{4\times 3.14\times (5.87 \times 10^7\:\rm{m})^3}

=692kg/m3=6.92×105g/m3=692\:\rm{kg/m^3}=6.92\times 10^5\:\rm{g/m^3}

The surface area of the Saturn


A=4πR2A=4\pi R^2

=4×3.14×(5.87×107m)2=4.33×1016m2=4\times 3.14\times (5.87\times 10^7\:\rm{m})^2=4.33\times 10^{16}\:\rm{m^2}


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