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Question #93299
Planet Saturn =5.87 * 10^7 m and it's mass is 5.86 * 10^26 Kg find the density of its material by g/m3
Find it's surface area by m2( 4πr^2)
Expert's answer
The density of the Saturn
ρ
=
M
V
=
M
4
3
π
R
3
=
3
M
4
π
R
3
\rho=\frac{M}{V}=\frac{M}{\frac{4}{3}\pi R^3}=\frac{3M}{4\pi R^3}
ρ
=
V
M
=
3
4
π
R
3
M
=
4
π
R
3
3
M
=
3
×
5.86
×
1
0
26
k
g
4
×
3.14
×
(
5.87
×
1
0
7
m
)
3
=\frac{3\times 5.86\times 10^{26}\:\rm{kg}}{4\times 3.14\times (5.87 \times 10^7\:\rm{m})^3}
=
4
×
3.14
×
(
5.87
×
1
0
7
m
)
3
3
×
5.86
×
1
0
26
kg
=
692
k
g
/
m
3
=
6.92
×
1
0
5
g
/
m
3
=692\:\rm{kg/m^3}=6.92\times 10^5\:\rm{g/m^3}
=
692
kg/
m
3
=
6.92
×
1
0
5
g/
m
3
The surface area of the Saturn
A
=
4
π
R
2
A=4\pi R^2
A
=
4
π
R
2
=
4
×
3.14
×
(
5.87
×
1
0
7
m
)
2
=
4.33
×
1
0
16
m
2
=4\times 3.14\times (5.87\times 10^7\:\rm{m})^2=4.33\times 10^{16}\:\rm{m^2}
=
4
×
3.14
×
(
5.87
×
1
0
7
m
)
2
=
4.33
×
1
0
16
m
2
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