Answer to Question #90846 in Physics for Crystal

Question

You are standing at a distance of 10.0 m from a speaker. The sound intensity is some value. You walk to a distance 4 times farther. How is the sound intensity affected?

Answer 1

In accordance with the law of conservation of energy

$$I\cdot4\pi R^{2} = const,$$

respectively

$$I_2 = I_1(\frac{R_1}{R_2})^{2} = \frac{I_1}{16},$$

i.e. intensity will decrease by 16 times.