Question

A 123.1 g sample of water at 25.5°C is heated to steam at 126.5°C. How much heat was absorbed?

Answer 1

The total heat equals to

$$Q=0.1231(74.5\cdot4.2\cdot10^{3} +2.26\cdot10^{6}+ 4\cdot8.31\frac{10^3}{18}26.5)$$

i.e.

$$Q = 0.32 (MJ).$$