The weight of the block immersed in water
"W=mg-g\\rho_{\\rm{w}} V_{\\rm{im}}"So
"W=g\\rho_{\\rm{b}}V_{\\rm{b}}-g\\rho_{\\rm{w}}V_{\\rm{b}}\/2""=9.8\\:\\rm{N\/kg}\\times 24000\\:\\rm{kg\/m^3}\\times 20\\times 10^{-6}\\rm{m^3}"
"-9.8\\:\\rm{N\/kg}\\times 1000\\:\\rm{kg\/m^3}\\times 20\\times 10^{-6}\\rm{m^3}\/2"
"=4.6\\:\\rm{N}"
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