Answer to Question #88025 in Physics for Andrew

Question

The solution of a problem is given as x=3.345 and it is known that the relative error is not more than 0.01. Find to 4 decimal places the range of values within which the exact value of the solution must lie.

Answer 1

The absolute error is

$$\Delta x=0.01(3.345)=0.0335$$

The range of values within which the exact value of the solution must lie.:

$$(3.345-0.0335, 3.345+0.0335)=(3.3115,3.3785)$$