Question

A force of 10 N keeps a wooden box moving at a steady speed of 5 m/s , on a wooden floor . If the mass of the box is 5kg, calculate the coefficient of kinetic friction?

Answer 1

For moving at  a steady speed we need:

$$F=F_f$$

$$F=\mu_k mg$$

$$\mu_k=\frac{F}{mg}=\frac{10}{(5)(10)}=0.2$$