Answer to Question #85596 in Physics for Anand

Question #85596

The molar heat capacity of a metal at 25 K is 31.06 J/ mol/K Determine its Debye
Temperature

Expert's answer

At low temperatures molar heat capacity of a metal:

"c_v=2.4\u03c0^4 R(T\/T_D )^3"

Thus, it’s Debye Temperature:

"T_D=25((2.4\u03c0^4 (8.31))\/31.06)^(1\/3)=99 K."

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