Question

The molar heat capacity of a metal at 25 K is 31.06 J/ mol/K Determine its Debye
Temperature

Answer 1

At low temperatures molar heat capacity of a metal:

$$c_v=2.4π^4 R(T/T_D )^3$$

Thus, it’s Debye Temperature:

$$T_D=25((2.4π^4 (8.31))/31.06)^(1/3)=99 K.$$