A 1290-kg car pulls a 270-kg trailer. The car exerts a horizontal force of 3.6 × 103 N against the ground in order to accelerate.
What force does the car exert on the trailer? Assume an effective friction coefficient of 0.16 for the trailer.
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Expert's answer
2019-02-19T14:53:08-0500
The Newton’s second law for a car
Ma=F-T
The Newton’s second law for a trailer
ma=T-F_frict=T-μmg
By combining two equations, we obtain
T=(m(F+μMg))/(m+M)
=(270(3.6×〖10〗^3+0.16×1290×9.81))/(270+1290)=974 N
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