Question

1 kg of copper at a temperature at 840 degrees is transferred into lad container holding 1.5 kg of ice at 0 degrees. the specific latent heat of fusion of ice is equal to 3.36×10^5 j/kg and specific heat capacity of copper is 400 j/kg/k. neglecting heat capacity of the container and heat loss yo surrounding, the amount of melted ice is?

Answer 1

From the conservation of energy:

m_copper c(T-T_ice )=m_ice h

(1)(400)(840-0)=m_ice (3.36∙〖10〗^5)

m_ice=1 kg.