The position of the body
x(t)=x_0+v_0 t+(at^2)/2
x(2)=5+3×2+(4×2^2)/2=19 m
The velocity of the body
v(t)=v_0+at
v(2)=3+4×2=11 m/s
v(t)=3+4t=5
t=0.5 s
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment