Question

A simple pendulum of length 0.4m has a period of 2.4s. The period of a simple pendulum of length 0.36 is

Answer 1

The time period of a simple pendulum for small amplitude of oscillations depends on the length

of the pendulum

$$L$$

and the acceleration due to gravity

$$g$$

, and can be found as follows:

$$T = 2 \pi \sqrt{\frac{L}{g}} = 2 \pi \sqrt{\frac{0.36 m}{9.8 \frac{m}{s^2}}} = 1.2 s.$$

Answer:

$$T = 1.2 s$$

.