The time period of a simple pendulum for small amplitude of oscillations depends on the length
of the pendulum
"L"and the acceleration due to gravity
"g", and can be found as follows:
"T = 2 \\pi \\sqrt{\\frac{L}{g}} = 2 \\pi \\sqrt{\\frac{0.36 m}{9.8 \\frac{m}{s^2}}} = 1.2 s."Answer:
"T = 1.2 s".
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