We can find the distance traveled by the cyclist from the kinematic equation:
"d = v_0t + (1\/2)at^2,"here,
"d"is the distance traveled by the cyclist,
"v_0 = 12.0 m\/s"is the initial speed of the cyclist,
"a = -2.5 m\/s^2"is the deceleration of the cyclist and
"t"is the time.
Let's substitute the numbers:
"d = 12.0 m\/s * 5 s + (1\/2)*(-2.5 m\/s^2)*(5.0 s)^2 = 28.75 m."
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