Question

The small piston of a hydrolic lifts has an area of 0.2m^2 a car weighing 1.2*10^4N sit on a rack mounted on the large piston. The large piston has an area of 0.9m^2 how large a force must be applied to the small piston to support the car

Answer 1

Answer on Question 83637, Physics, Other

Question:

The small piston of hydraulic lift has an area of

$$0.2 m^2$$

. A car weighing

$$1.2*10^4 N$$

sits on a rack mounted on the large piston. The large piston has an area of

$$0.9 m^2$$

. How large a force must be applied to the small piston to support the car?

Solution:

By the hydraulic press formula, we have:

$$F_1/A_1=F_2/A_2$$

,

here,

$$A_1$$

is the area of the small piston,

$$A_2$$

is the area of the large piston,

$$F_1$$

is the force applied to the small piston,

$$F_2$$

is the force applied to the large piston.

From this formula we can find the force applied to the small piston:

$$F_1=F_2*(A_1/A_2)=1.2*10^4 N*(0.2 m^2/0.9 m^2)=2.7*10^3 N$$

.

Answer:

$$F_1=2.7*10^3 N$$

.