Answer on Question 83629, Physics, Other
Question:
You weigh
"740 N". What would you weigh if the Earth were two times as massive as it is and its radius were three times its present value? Answer in units of N.
Solution:
From the definition of the weight, we have:
"W=mg"
,
here,
"m"is the mass of the person,
"g"is the acceleration due to gravity.
By the definition of the acceleration due to gravity, we have:
"g=GM_E\/R_E^2"
,
here,
"G"is the universal gravitational constant,
"M_E"is the mass of the Earth and
"R_E"is the radius of the Earth.
Substituting the expression for
"g"into the first equation, we get:
"W=mg=mGM_E\/R_E^2\u221dM_E\/R_E^2"
.
Then, we can find the new weight from the relationship:
"Wnew\/W=M_Enew\/(R_Enew)^2\/(M_E\/R_E^2)"
,
"Wnew\/W=2M_E\/(3R_E)^2\/(M_E\/R_E^2)=2\/9"
.
Finally, we get:
"Wnew=(2\/9)W=(2\/9)*740 N=164 N"
.
Answer:
"Wnew = 164 N".
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