Answer to Question #83161 in Physics for Richie Guchie

Question #83161

If a body of mass 45kg is pushed down an inclined plane 60° to the horizontal find the component of the weight along xy direction take G=9.8 meter second square

Expert's answer

The component of the weight along this direction is

F=mg sin⁡60

F=(45)(9.8) sin⁡60=380 N.

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