Question

A cyclist negotiating a circular track of radius 12cm can attain a maximum speed of 8.4m per secs without slipping. Determine the frictional force which would act to prevent the side slip; taking the mass of the cycle and cyclist as 80kg (Take g=10m per sec square)

Answer 1

The frictional force which would act to prevent the side slip:

F=(mv^2)/r

F=(80〖(8.4)〗^2)/0.12=47000 N=47 kN.