F=μmg
The coefficient of static friction:
μ=F/mg=11.8/((2)(9.81))= 0.601
2. A woman is skiing straight down the snow covered hill. The coefficient of kinetic friction between the skis and the snow is 0.0800. The hill is at 60.0 degree angle form the horizontal. The skier mass is 55.00 kg. What is the magnitude of the force of kinetic friction, and what is the net force along the skiers motion?
Solution
The magnitude of the force of kinetic friction
F=μmg=(0.08)(55)(9.81)=43.2 N.
The net force along the skiers motion
F_net=mg sin60-μmg cos60
F_net=(55)(9.81)(sin60-0.08 cos60 )=446 N.
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