In order to determine which step the ball lands on, the ball must fall at least a distance equal to its horizontal displacement.
t_1 =x_1/v_x =0.5/3 = 0.17 s,
y_1= (1/2)at_1^2=1/2 (9.8) (0.5/3)^2 = 0.14 m.
So the ball goes past the first step.
t_4 =x_1/v_x =4 0.5/3 = 0.67 s,
y_4= (1/2)at_4^2=1/2 (9.8) (4 0.5/3)^2= 2.18 m.
x_4=4(0.5)=2 m<y_4=2.18.
So the ball lands on the fourth step.
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