Answer to Question #81258 in Physics for slkdslak

Question

A ball is thrown upward with an initial velocity of 14m/s
what are the magnitude and the direction of the ball s velocity

3 seconds after it is thrown?

Answer 1

We can find the ball’s velocity from the kinematic equation:
v=v_0-gt,
here, v_0=14 m⁄s is the initial velocity of the ball, v is the velocity of the ball at time t=3 s and g=9.8 m⁄s^2 is the acceleration due to gravity.
Then, we get:
v(t=3 s)=14 m/s-9.8 m/s^2 ∙3 s=-15.4 m/s .
The sign minus indicates that the ball’s velocity directed downward.