Answer to Question #80886 in Physics for ronald kramer

Question #80886

An object is projected horizontally at 15 m/s. At the same time, another object located 9 meters down range is dropped from rest. When will the two objects collide?

Expert's answer

y_1=y_2=-(gt^2)/2.
x=vt
t=x/v=9/15=0.6 s.

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