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Answer to Question #80885 in Physics for ronald kramer
Question #80885
A football is thrown with an initial velocity of 43 mph at an angle of 35 degrees. How many yards down the field does the ball land?
Expert's answer
1 mph=0.44704 m/s
R=v^2/g sin〖2(θ)〗
R=〖(0.44704∙43)〗^2/9.8 sin70=35.43 m=35.43(1.09361)yards=39 yards.
R=v^2/g sin〖2(θ)〗
R=〖(0.44704∙43)〗^2/9.8 sin70=35.43 m=35.43(1.09361)yards=39 yards.
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