Question

A golf ball leaves the tee with a velocity of 75 ft/s at 30 degrees. If it lands on a green located 8 feet higher than the tee, what was the time of flight, and what was the horiztonal distance to the green?

Answer 1

g=32.174 ft/s^2
The height of the projectile is
y=h+v sin⁡θ t-1/2 gt^2.
0=8+75 sin⁡30 t-1/2(32.174)t^2.
The time of flight:
t=2.53 s.
The horizontal distance to the green:
R=v cos⁡θ t=75 cos⁡30 (2.53)=164 ft.