Answer to Question #80874 in Physics for Sahil

Question #80874

A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same speed how high above the ground can the cricketer throw the same ball?

Expert's answer

The maximum horizontal distance of projectile:
R=v^2/g.
The maximum height of projectile:
H=v^2/2g=R/2=100/2=50 m.

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