If V sub x=9.80 units and v sub y= -6.40 units determine the magnitude and direction of vector V
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Expert's answer
2018-09-07T16:17:08-0400
a) We can find the magnitude of the vector V ⃗ from the formula: |V ⃗ |=√(V_x^2+V_y^2 )=√(〖9.80〗^2+(-6.40)^2 )=11.7 units. b) We can find the direction of the vector V ⃗ from the formula: tanθ=V_y/V_x , θ=tan^(-1)〖(V_y/V_x )=tan^(-1)〖((-6.40)/9.80)=〖-33〗^° 〗 〗. However, we must add 〖360〗^° to obtain the correct answer: θ=〖-33〗^°+〖360〗^°=〖327〗^°. The angle between the vector V ⃗ and the positive x-axis is 〖327〗^° (counterclockwise).
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