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Answer to Question #80044 in Physics for Sherwin
Question #80044
A 20 kW motor lifts a load at a speed of 0.4 m/s. What is the maximum load it can lift at this speed
Expert's answer
The formula for the power is
P=Fv.
The maximum load it can lift at this speed is
F=P/v=20000/0.4=50 kN.
Answer: 50 kN.
P=Fv.
The maximum load it can lift at this speed is
F=P/v=20000/0.4=50 kN.
Answer: 50 kN.
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