Question

A Revolver of mass 500g fires A bullet of mass 10g with a speed of 100m/s find (1) momentum of the bullet (2) initial momentum of revolver and Bullet as a system (3) recoil velocity of the revolver

Answer 1

Answer on Question 79671, Physics, Other

Question:

A revolver of mass $500\,g$ fires a bullet of mass $10\,g$ with a speed of $100\,m/s$. Find the following:

1) momentum of the bullet;

2) initial momentum of revolver and bullet as a system;

3) recoil velocity of the revolver.

Solution:

1) We can find the momentum of the bullet from the formula:

$$p_b = m_b v_b = 0.01\,kg \cdot 100\,\frac{m}{s} = 1\,kg \cdot \frac{m}{s}.$$

2) Initially both the revolver and the bullet are at rest, therefore the initial momentum of the system is zero:

$$p_i = m_b v_{b\,(initial)} + M_r v_{r\,(initial)} = 0.$$

3) We can find the recoil velocity of the revolver from the law of conservation of momentum:

$$p_i = p_f,$$ $$M_r v_{recoil} + m_b v_b = 0,$$ $$M_r v_{recoil} = -m_b v_b,$$ $$v_{recoil} = -\frac{m_b v_b}{M_r} = -\frac{0.01\,kg \cdot 100\,\frac{m}{s}}{0.5\,kg} = -2\,\frac{m}{s}.$$

The sign minus indicates that the recoil velocity of the revolver directed in the opposite direction to the velocity of the bullet.

Answer:

1) $p_b = 1\,kg \cdot \frac{m}{s}$.

2) $p_i = 0$.

3) $v_{recoil} = -2\,\frac{m}{s}$.

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