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Answer to Question #79590 in Physics for Simran kar
Question #79590
If y=x (to the power 7÷2) find dy÷dx
Expert's answer
y=x^(7/2 )
Apply the Power Rule:
dy/dx (x^a )=a∙x^(a-1)
So,
dy/dx (x^(7/2 ) )=7/2∙x^(7/2-1)=7/2 x^(5/2)
Apply the Power Rule:
dy/dx (x^a )=a∙x^(a-1)
So,
dy/dx (x^(7/2 ) )=7/2∙x^(7/2-1)=7/2 x^(5/2)
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