Answer to Question #79360 in Physics for Faith

Question

Rescue plane is flying horizontally at a height of 97 m above the ground. The pilot spots a survivor and releases an emergency kit with a parachute. The kit descends at a constant vertical acceleration of and the initial plane horizontal speed is . Assuming air resistance and wind are negligible, how far away from the survivor will the emergency kit hit the ground?

Answer 1

The time of flight is
t=√(2h/a).
So,
x=vt=v√(2h/a)
x=66.4 √(2(97)/6.63)=359 m.