Question #79054

What is the potential difference in a circuit of 100 ma and 5 ohms?

This problem consist of using the OHMS LAW equation: V= I * R
Where:
V= potential difference in volts
R= resistance ohms
I= current in amps
I also understand that 1 ma ( milliamperage) = 0.001 amp , hence, milli meaning 10^-3, which is why it is converted to 0.1. although even after the conversions, the answer is still not right? Am i adding a step? Do i have to remove the converting step and just follow the formula as is?
I do not want the answer, i want to know how to solve it. I have tried using the triangle method but it is not the right answer.

Expert's answer

1) The conversion:
100 mA=100∙〖10〗^(-3) A=0.1 A.
2) Ohms law:
V=IR
V=(0.1)(5)=0.5 V.
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