Question #78608

the world record for the women's 100m sprint in 1993 stood at 10.49 s.a)what average speed does this represent?b)if the athlete accelerates to a steady speed in the first 1.5 s of the race and then runs at this speed until reaching the finishing line , at what steady speed does she run?(hint:solve by drawing the velocity time graph)
1

Expert's answer

2018-06-26T09:30:08-0400

Question #78608, Physics / Other

the world record for the women's 100m sprint in 1993 stood at 10.49 s.

a) what average speed does this represent?


v=dt=10010.49=9.53m/sv = \frac {d}{t} = \frac {100}{10.49} = 9.53 \mathrm{m/s}


b) if the athlete accelerates to a steady speed in the first 1.5 s of the race and then runs at this speed until reaching the finishing line, at what steady speed does she run? (hint: solve by drawing the velocity time graph)



Let xx represent the steady speed.

The distance is calculated as follows.


d=12×1.5×x+(10.491.5)x=9.74x=100d = \frac {1}{2} \times 1.5 \times x + (10.49 - 1.5) x = 9.74 x = 100


Solving for xx, obtaining x=10.27m/sx = 10.27 \, \text{m/s}

Answer: a. 9.53m/s9.53 \, \text{m/s}; b. 10.27m/s10.27 \, \text{m/s}.

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