Answer to Question #77636 in Physics for Muhammad Zeeshan

Question

Two bodies A and B of masses mA = 1 kg and mB are initially at rest at the same height y0 = 80 cm above a horizontal plane. At t = 0 they are both releases. A slides along a plane inclined by an angle θ = 45° while B falls vertically. Let tA and tB be the time required for A and B to reach the horizontal plane, vA and vB are the corresponding speed at tA and tB. Which of the following results is correct? (Assume g = 10 m/s2)
vA = 1/2 vB and tA = tB = 0.4 s
vA = 2 vB and tA = tB = 0.4 s
vA = vB = 4 m/s and tA = √2tB
vA = vB = 4 m/s and tA = 1/2tB = 0.8 s
vA = vB = 4 m/s and tA = 1/√2tB

Answer 1

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