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Answer to Question #76786 in Physics for sal
Question #76786
A 10 kg rock is thrown up. It is moving at 9 m/s. What is its potential energy at the top? (Hint: conservation of energy)
Expert's answer
The law of conservation of energy states
KE+PE=const
So
PE_final=KE_initial
PE_final=(mv_i^2)/2=(10×9^2)/2=405 J
KE+PE=const
So
PE_final=KE_initial
PE_final=(mv_i^2)/2=(10×9^2)/2=405 J
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