Question #76673
A spring of force constant 1500N/m is acted upon by a force constant of 75N.Calculate the potential energy stored in the spring.
Expert's answer
First, let’s calculate the compression of the spring from the Hooke’s law:
F=kx,
here, F=75 N is the force acted on the spring, k=1500 N⁄m is the force constant of the spring, x is the compression of the spring.
Then, we get:
x=F/k=(75 N)/(1500 N/m)=0.05 m.
Finally, we can find the potential energy stored in the spring:
PE=1/2 kx^2=1/2∙1500 N/m∙(0.05 m)^2=1.875 J.
F=kx,
here, F=75 N is the force acted on the spring, k=1500 N⁄m is the force constant of the spring, x is the compression of the spring.
Then, we get:
x=F/k=(75 N)/(1500 N/m)=0.05 m.
Finally, we can find the potential energy stored in the spring:
PE=1/2 kx^2=1/2∙1500 N/m∙(0.05 m)^2=1.875 J.
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Please can u help me solve this problem in physics *Assignment* A stone of mass 2kg is released from a catapult whose rubber has been stretched through 40mm. If the force constant of the rubber is 200N/m. Calculate the velocity with which the stone leaves the catapult?
Dear Marcus Sulonteh, as you can see 1/2∙1500 N/m∙(0.05 m)^2=1.875 J
How did you get the 1.8 in the problem?