Answer to Question #76655 in Physics for Fatima

Question

An object droppin from 70m high lower find its position after 1 second

Answer 1

We can find the position of an object after 1 second from the kinematic equation:
y(t)=y_0+v_0 t-1/2 gt^2,
here, y(t) is the position of an object at any time t, y_0=70 m is the initial position of an object, v_0=0 is the initial velocity of an object, g=9.8 m⁄s^2 is the acceleration due to gravity.
Then, we get:
y(t=1 s)=70 m-1/2∙9.8 m/s^2 ∙(1.0 s)^2=65.1 m.