We can find the escape velocity from the Moon as follows: v_escape=√((2GM_Moon)/R_Moon ), here, G=6.673∙〖10〗^(-11) (Nm^2)⁄〖kg〗^2 is the universal gravitational constant, M_Moon=7.35∙〖10〗^22 kg is the mass of the Moon and R_Moon=1.74∙〖10〗^6 m is the radius of the Moon. Then, we get: v_escape=√((2GM_Moon)/R_Moon )=√((2∙6.673∙〖10〗^(-11) (Nm^2)/〖kg〗^2 ∙7.35∙〖10〗^22 kg)/(1.74∙〖10〗^6 m))=2374 m/s≈≈2.37 km/s. Answer: v_escape=2374 m/s≈2.37 km/s.
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