Answer to Question #74920 in Physics for Moko Malachy

Question

Calculate the escape velocity from the moon?

Answer 1

We can find the escape velocity from the Moon as follows:
v_escape=√((2GM_Moon)/R_Moon ),
here, G=6.673∙〖10〗^(-11) (Nm^2)⁄〖kg〗^2 is the universal gravitational constant, M_Moon=7.35∙〖10〗^22 kg is the mass of the Moon and R_Moon=1.74∙〖10〗^6 m is the radius of the Moon.
Then, we get:
v_escape=√((2GM_Moon)/R_Moon )=√((2∙6.673∙〖10〗^(-11) (Nm^2)/〖kg〗^2 ∙7.35∙〖10〗^22 kg)/(1.74∙〖10〗^6 m))=2374 m/s≈≈2.37 km/s.
Answer:
v_escape=2374 m/s≈2.37 km/s.